Control 01 Semester 02 en Trigonometrie (D)
📅 March 19, 2025 | 👁️ Views: 13

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%%%%%%%%%%%%%%%%%%%%%%%%%%%% Start of the exam %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\noindent
\exo{Exercice 1: (\textit{12 pts}) }\\
\hspace*{0.3cm}Soit la figure suivante:
\begin{questions}
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donner les mesures :
\((\overline{\overrightarrow{BA},\overrightarrow{BC}})\);
\((\overline{\overrightarrow{CA},\overrightarrow{CB}})\);
\((\overline{\overrightarrow{DC},\overrightarrow{DB}})\);
\((\overline{\overrightarrow{AB},\overrightarrow{AC}})\)
\question[2]
Vérifier que \(\frac{45\pi}{4}\) et \(\frac{-3\pi}{4}\)
Sont des abscisses curvilignes du même point.\\
Puis le placer sur le cercle trigonométrique
\question[3]
Simplifier:
\(A= 2\cos x +3\cos(\pi+x) +6\sin(\frac{\pi}{2}-x)\)
\question[3]
Calculer:
\(B= \sin^2\frac{\pi}{12} + \sin^2\frac{3\pi}{12}+\sin^2\frac{5\pi}{12}\)
\end{questions}
\exo{Exercice 2: (\textit{8 pts}) }
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\question[$1.5\times2$+3]
Résoudre les équations et inéquation suivantes:\\
$x\in \mathbb R \quad \sin\left(x\right)=\frac{\sqrt2}{2}\quad$; ~~~
$x\in ]-2\pi,3\pi]\quad \sqrt3+2\sin x =0\quad$ ;
$\quad x\in ]-2\pi,3\pi]\quad \sin x > -\frac{1}{2}$
\question[2]
Résoudre dans \(\mathbb{R}\quad\) \(\begin{cases}
\cos x = \cos y\\
3x+2y=\pi
\end{cases}\)
\question[2]
\textbf{Bonus Question}: Résoudre
$\quad x\in ]-\pi,\pi]\quad 2\sin^2(7\pi+x)-3\sqrt3\cos\left(\frac{9\pi}{2}-x\right)+3\ge0$\\
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