Devoir à la maison 02 - S01, Calcul et ordre dans IR, Droite dans le plan

📅 December 01, 2025   |   👁️ Views: 840   |   📝 4 exercises



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% --- Basic Settings ---
\def\professor{R. MOSAID}
\def\classname{TCSF}
\def\examtitle{Devoir à la maison 02 - S01 / TCSF}
\def\schoolname{\textbf{Lycée :} Taghzirt}
\def\academicyear{2025/2026}
\def\subject{Calcul et ordre dans IR, Droite dans le plan }
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% Exercise 1
\printexo{1}{}{
Le plan est rapporté à un repère orthonormé $(O; \vec i, \vec j)$\\
Soient les points ~$A(5,-3$~, ~$B(3,-1)$~ , ~$C(2,-3)$~ et ~$D(-1,2)$\\
\textbf{1}~$-$ Est ce que les points ~$A$~, ~$B$~ et ~$C$~ sont alignés?\\
\textbf{2}~$-$ Donner une équation cartésienne de la droite ~$(AB)$\\
\textbf{3}~$-$ Donner une représentation paramétrique de la droite ~$(AC)$\\
\textbf{4}~$-$ Donner une équation cartésienne de la droite ~$(\Delta)$~ passant par ~$C$~
et parallèle à ~$(AB)$\\
\textbf{5}~$-$ Construir la figure
}
% Exercise 2
\printexo{2}{}{
\textbf{1}~$-$ Soient les intervalles: ~$I=\left[\frac{13}{6},+\infty\right[$~ , ~$J=\left]2,\frac{7}{3}\right[$~
et ~$K=\left]-\infty,\frac{25}{12}\right]$\\
\hspace*{2cm} Déterminer ~$I\cap J$~, ~$I\cup J$~, ~$I\cap K$~, ~$I\cup K$~, ~$J\cap K$~, ~$J\cup K$\\
\textbf{2}~$-$ Résoudre dans ~$\mathbb{R}$:~ ~$|3x-3|=|2x-4|$~ et ~$|2x-7|\le 4$\\
\textbf{3}~$-$ Soient ~$-2<x<1$~ et ~$-3<y<-1$~ et ~$A=x^2+x-2$\\
\hspace*{0.5cm}\textbf{a}~$-$ Encadrer ~$xy$~, ~$y^2$~ , ~$A$~ et ~$\frac{A}{x-4y}$~ \\
\hspace*{0.5cm}\textbf{b}~$-$ Montrer que ~$A=(x-1)(x+2)$~ puis donner un meilleur encadrement pour ~$A$
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% Exercise 3
\printexo{3}{}{
\textbf{1}~$-$ Développez l'expression suivante : \( A = \left( 2\sqrt{3} - 3\sqrt{2} \right)^3 \)\\
\textbf{2}~$-$ Considérons \( a \) et \( b \) tels que : $ab = -\frac{1}{3} \quad \text{et} \quad a + b = \sqrt{2}$~~
Calculez : $a^3 + b^3 \quad \text{et} \quad a^2 + b^2$\\
\textbf{3}~$-$ Donnez l'écriture décimale et scientifique du nombre \( B \), où :
$B = \frac{3 \cdot 10^{-3} \cdot \left( 2 \cdot 10^{-6} \right)^2}{15 \cdot \left( 10^2 \right)^{-3}}$\\
\textbf{4}~$-$ Soient \( a \) et \( b \) tels que : ~$16a + 12b = 5$~
Simplifiez l'expression : ~$C = (a + 8)^2 - (a - 8)^2 + (b + 6)^2 - (b - 6)^2$\\
\textbf{5}~$-$ Considérons : ~$D = -\sqrt{2 + \sqrt{3}} + \sqrt{2 - \sqrt{3}}$\\
\hspace*{1cm} \textbf{a}~$-$ Montrez que le signe de \( D \) est négatif.\\
\hspace*{1cm} \textbf{b}~$-$ Calculez \( D^2 \), puis déduisez la valeur simplifiée de \( D \).\\
\textbf{6}~$-$ Factoriser ~$E=3\sqrt3x^3+2\sqrt2-4x(3x^2-2)+3x^2+2\sqrt{6}+4$
}

% Exercise 4
\printexo{4}{}{
Soient $a$ une valeur approchée par defaut de $\frac{1}{3}$ ~~à~~ $2 \times 10^{-1}$ près. et $b$ tel que
$2b^2-b-1<0$\\[0.3cm]
\textbf{1}~$-$ Montrer que ~$\frac{2}{15}\le a\le \frac{1}{3}$~ puis encadrer $\frac{a}{a-1}$\\[0.3cm]
\textbf{2}~$-$ Soit $x\in\mathbb{R}$ tel que $\left|\frac{x-1}{a}\right|<\frac{1}{10} $
~Montrer que $\frac{29}{30}<x<\frac{31}{30}$\\[0.3cm]
\textbf{3}.a~$-$ Montrer que :
~~$2b^2-b-1=2\left(b- \frac{1}{4}\right)^2-\frac{9}{8}$\\[0.3cm]
\hspace*{0.2cm}.b~$-$ Montrer que $\frac{-1}{2}<b<2$ ~~puis encadrer $b^2-a$
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Frequently Asked Questions

What chapters or courses does this exam cover?
This exam covers: مجموعات الأعداد, Ensembles des nombres, مجموعات الأعداد نسخة 2, L'ordre dans IR - partie 2, L'ordre dans IR - partie 1, الترتيب في IR, الترتيب في IR نسخة 2, المستقيم في المستوى نسخة 2, المستقيم في المستوى. It is designed to test understanding of these topics.

How many questions are in this exam?
The exam contains approximately several questions.

Is this exam aligned with the official curriculum?
Yes, it follows the tronc-commun-sciences maths guidelines.

What topics are covered in this course?
The course "L'ordre dans IR" covers key concepts of maths for tronc-commun-sciences. Designed to help students master the curriculum.

Is this course suitable for beginners?
Yes, the material is structured to be accessible while providing depth for advanced learners.

Are there exercises or practice problems?
This resource includes 4 exercise(s) to reinforce learning.

Does this course include solutions?
Solutions are available separately.


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