Devoir 3 S01 - Nombres Décimaux Relatifs et Géométrie
📅 April 18, 2024 | 👁️ Views: 230
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\documentclass[12pt,a4paper]{article}
\usepackage[landscape, margin=1cm]{geometry} % Set landscape layout and margins
\usepackage{amsmath,amsfonts,amssymb}
\usepackage{tabularx,tabulary}
\usepackage{array} % Add the array package for 'm' column type
\usepackage{graphicx}
\usepackage{booktabs}
\usepackage{fontenc}
\usepackage{setspace}
\usepackage{xcolor}
\setstretch{1.5}
\newcommand\ddfrac[2]{\frac{\displaystyle #1}{\displaystyle #2}}
\begin{document}
\thispagestyle{empty}
\newcolumntype{M}[1]{>{\centering\arraybackslash}m{#1}}
\begin{minipage}[t]{0.48\linewidth}
\setlength{\parindent}{0pt} % Remove the inner margin
\setlength{\parskip}{0pt}
\noindent
\begin{tabularx}{\linewidth}{|M{0.30\linewidth}|M{0.25\linewidth}|M{0.35\linewidth}|}
\hline
Collège Tariq Ben Ziad 2
&
Devoir Surveillé N 3
&
Année Scolaire 2023-2024
\\ \hline
Prof : MOSAID
&
1APIC-A
&
durée : 1h
\\ \hline
\end{tabularx}
\begin{tabularx}{\linewidth}{|p{0.965\linewidth}|}
Nom et prénom : \\
\hline
\end{tabularx} \\
\noindent
\underline{\textbf{Exercice 1:}}\\
1)- Construir un triangle \(ABC\) isocèle en \(A\) tel que \(A\hat BC=50^\circ\) \\
2)- Placer le point \(I\) le milieu du segment \([AB]\).\\
3)- Construir la mediane du triangle \(ABC\) passant par le sommet \(C\).\\
4)- Construir la hauteur passant par le sommet \(B\)\\
5)- Construir la médiatrice du segment \([BC]\)\\
\end{minipage}
\hspace{0.01\linewidth}
\vline
\hspace{0.01\linewidth}
\begin{minipage}[t]{0.48\linewidth}
\setlength{\parindent}{0pt} % Remove the inner margin
\setlength{\parskip}{0pt}
\vspace*{-0.5cm}
6)- Completer par ce qui convient:\\
On sait que la ........................ des angles d'un triangle est .........\\
Donc \(A\hat BC + ..........+........ = .....\)\\
Or le triangle \(ABC\) est isocèle donc \(........... = ............ = 50^\circ\)\\
Alors \(A\hat CB = ............- (A\hat BC + ..............)\)\\
Donc \(A\hat CB =\dotfill\)\\
\hspace*{0.4cm}=\dotfill\\
\underline{\textbf{Exercice 2:}}\\
Enlever les parenthèses avant de calculer: \\
$A=7-(4-15)+(-7-15)$\\
\hspace*{0.4cm}=\dotfill\\
\hspace*{0.4cm}=\dotfill\\
\hspace*{0.4cm}=\dotfill\\
$B=-10-[5-(4-14)-10]$\\
\hspace*{0.4cm}=\dotfill\\
\hspace*{0.4cm}=\dotfill\\
\hspace*{0.4cm}=\dotfill\\
$B=-13-(-3+10)-10+(5-8)-(13-10)$\\
\hspace*{0.4cm}=\dotfill\\
\hspace*{0.4cm}=\dotfill\\
\hspace*{0.4cm}=\dotfill\\
\hspace*{0.4cm}=\dotfill\\
\end{minipage}
\textcolor{white}{.}\hfill \textbf{\underline{Bonne Chance}}\\
\end{document}
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This exam covers: the relevant chapters. It is designed to test understanding of these topics.
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The course "Devoir 3 S01 - Nombres Décimaux Relatifs et Géométrie" covers key concepts of maths for 1apic. Designed to help students master the curriculum.
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