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\node[anchor=west,rotate=90,fill=yellow] at ([shift={(0.5,2)}]current page.south west){\color{red!75!black}\textbf{{\Large Mathématiques}}};
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\begin{document}
%\vspace*{1cm}
\begin{Exercice}{Exercice 1 }
{\small
\begin{enumerate}
\item La limite $\lim _{\substack{x \rightarrow 3 \\ x>3}} \frac{x}{3-x}$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] $\frac{1}{3}$
\item[$\square$] $ 0 $
\item[$\square$]  $-\infty$
\item[$\square$] $+\infty$
\end{itemize}
\end{multicols}
\item La limite $\lim _{x \rightarrow 0} \frac{\sqrt{1+x^2}-1}{x}$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] $+\infty$
\item[$\square$] $ -1 $
\item[$\square$]  $ 0 $
\item[$\square$]  $ \dots $
\end{itemize}
\end{multicols}
\item  La limite $\lim _{x \rightarrow+\infty} \sqrt{x+1}-\sqrt{x}$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] 0
\item[$\square$] $+\infty$
\item[$\square$] $ 1 $
\item[$\square$] $-\infty$
\end{itemize}
\end{multicols}
\item  La limite $\lim _{x \rightarrow-\infty} \sqrt{9 x^2+x}-2 x$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] $ 2 $
\item[$\square$] $+\infty$
\item[$\square$] $ 1 $
\item[$\square$] $-\infty$
\end{itemize}
\end{multicols}
\item Soit $f$ un fonction définie sur $\mathbb{R}$ tel que $(\forall x \in \mathbb{R}): x^2-x \leq f(x) \leq x^2+x$. On a :
\begin{multicols}{3}
\begin{itemize}
\item[$\square$] $\lim _{x \rightarrow+\infty} f(x)=0 $
\item[$\square$] $ \lim _{x \rightarrow 0} f(x)=+\infty $
\item[$\square$] $ \lim _{x \rightarrow+\infty} f(x)=\dots $
\end{itemize}
\end{multicols}
\end{enumerate}}
\end{Exercice}
\begin{Exercice}{Exercice 2 }
{\small
\begin{enumerate}
\item La limite $\lim _{\substack{x \rightarrow 3 \\ x>3}} \frac{x}{3-x}$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] $\frac{1}{3}$
\item[$\square$] $ 0 $
\item[$\square$]  $-\infty$
\item[$\square$] $+\infty$
\end{itemize}
\end{multicols}
\item La limite $\lim _{x \rightarrow 0} \frac{\sqrt{1+x^2}-1}{x}$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] $+\infty$
\item[$\square$] $ -1 $
\item[$\square$]  $ 0 $
\item[$\square$]  $ \dots $
\end{itemize}
\end{multicols}
\item  La limite $\lim _{x \rightarrow+\infty} \sqrt{x+1}-\sqrt{x}$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] 0
\item[$\square$] $+\infty$
\item[$\square$] $ 1 $
\item[$\square$] $-\infty$
\end{itemize}
\end{multicols}
\item  La limite $\lim _{x \rightarrow-\infty} \sqrt{9 x^2+x}-2 x$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] $ 2 $
\item[$\square$] $+\infty$
\item[$\square$] $ 1 $
\item[$\square$] $-\infty$
\end{itemize}
\end{multicols}
\item Soit $f$ un fonction définie sur $\mathbb{R}$ tel que $(\forall x \in \mathbb{R}): x^2-x \leq f(x) \leq x^2+x$. On a :
\begin{multicols}{3}
\begin{itemize}
\item[$\square$] $\lim _{x \rightarrow+\infty} f(x)=0 $
\item[$\square$] $ \lim _{x \rightarrow 0} f(x)=+\infty $
\item[$\square$] $ \lim _{x \rightarrow+\infty} f(x)=\dots $
\end{itemize}
\end{multicols}
\end{enumerate}}
\end{Exercice}
\begin{Exercice}{Exercice 3 }
{\small
\begin{enumerate}
\item La limite $\lim _{\substack{x \rightarrow 3 \\ x>3}} \frac{x}{3-x}$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] $\frac{1}{3}$
\item[$\square$] $ 0 $
\item[$\square$]  $-\infty$
\item[$\square$] $+\infty$
\end{itemize}
\end{multicols}
\item La limite $\lim _{x \rightarrow 0} \frac{\sqrt{1+x^2}-1}{x}$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] $+\infty$
\item[$\square$] $ -1 $
\item[$\square$]  $ 0 $
\item[$\square$]  $ \dots $
\end{itemize}
\end{multicols}
\item  La limite $\lim _{x \rightarrow+\infty} \sqrt{x+1}-\sqrt{x}$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] 0
\item[$\square$] $+\infty$
\item[$\square$] $ 1 $
\item[$\square$] $-\infty$
\end{itemize}
\end{multicols}
\item  La limite $\lim _{x \rightarrow-\infty} \sqrt{9 x^2+x}-2 x$ égale :
\begin{multicols}{4}
\begin{itemize}
\item[$\square$] $ 2 $
\item[$\square$] $+\infty$
\item[$\square$] $ 1 $
\item[$\square$] $-\infty$
\end{itemize}
\end{multicols}
\item Soit $f$ un fonction définie sur $\mathbb{R}$ tel que $(\forall x \in \mathbb{R}): x^2-x \leq f(x) \leq x^2+x$. On a :
\begin{multicols}{3}
\begin{itemize}
\item[$\square$] $\lim _{x \rightarrow+\infty} f(x)=0 $
\item[$\square$] $ \lim _{x \rightarrow 0} f(x)=+\infty $
\item[$\square$] $ \lim _{x \rightarrow+\infty} f(x)=\dots $
\end{itemize}
\end{multicols}
\end{enumerate}}
\end{Exercice}
\end{document}