فرض محروس رقم 1 د 1

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            \hline
                    \qst{}{\ex{\textbf{ التمرين 01:($4,5$ نقط)}}}
\qst{1}{\q
بين أن:
$\arctan(1) +\arctan(2) +\arctan(3)=\pi$
.
}
\qst{1,5}{\q
بين أن:
$\forall x\in ]-1;1[: \arctan\bigg(\dfrac{2x} {1-x^2}\bigg)=2\arctan(x)$
.}

\qst{2}{\q
احسب النهايتين
:
}
\qst{}{
\hfil $\lim\limits_{x\longrightarrow +\infty}x\arctan\bigg({\dfrac{x+1}{x^2}}\bigg)$ \hfil $\lim\limits_{x\longrightarrow 0}\dfrac{\sqrt{1+2x^2}-\sqrt[3]{1+2x^2}}{\tan^2(x)}$
}


    \hline
%-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
                    \qst{}{\ex{\textbf{ التمرين 02:($7$ نقط)}}}

         \qst{}{نعتبر الدالة العددية
         $\varphi$
        المعرفة على
       $ \mathbb{R}$
        بما يلي
        :
        $\varphi(x)=x\sqrt{1+x^2}+1$
        .}

         \qst{1,5}{\q
         بين أن الدالة
         $\varphi$
         قابلة للاشتقاق على
         $\mathbb{R}$
         وأن
         :
         $\forall x \in \mathbb{R}:\varphi'(x)=\dfrac{1+2x^2}{\sqrt{1+x^2}}$
         .

         }
         \qst{0,5}{\q
         بين أن الدالة
         $\varphi$
         تقابل من
         $\mathbb{R}$
         نحو
         $\mathbb{R}$
         .}

         \qst{1}{\q استنتج أن المعادلة
         $\varphi(x)=0$
         تقبل حلا وحيدا
         $\alpha$
         في
         $\mathbb{R}$
         ثم تحقق أن
         :
         $-1<\alpha<0$
         .
         }
         \qst{1.5}{\q
بين أن الدالة
         $\varphi^{-1}$
         قابلة للإشتقاق في
         $0$
        وأن
        :
        $\big(\varphi^{-1}\big)'(0)=\dfrac{-1}{\alpha(1+2
        \alpha^2)}$
        .
        }

        \qst{1}{\q
    بين أن
    :
        $\forall x \in \mathbb{R}: 2\big(\varphi^{-1}(x)\big)^2=\sqrt{4x^2-8x+5}-1$
        .}

        \qst{1,5}{\q
        احسب من جديد
        $\big(\varphi^{-1}\big)'(0)$
        ثم بين أن
        :
        $\alpha=-\sqrt{\dfrac{\sqrt{5}-1}{2}}$
        .}

\hline
            \qst{}{\ex{\textbf{ التمرين 03:($8,5$ نقط)}}}
            \qst{}{ نعتبر الدالة العددية
            $f$
            المعرفة على
           $ \big[\dfrac{-1}{\sqrt{3}};+\infty\big[$
            بما يلي:

        ~$\begin{cases}
                      f(x)=\dfrac{4}{\pi} \arctan\big(\sqrt{1+x}\big)-1; x\ge0\\
                                  f(x)=\dfrac{1-\sqrt[3]{1-3x^2}}{x}; x<0
                                          \end{cases}$~
        .}

            \qst{0.5}{\q
احسب النهاية
:
            $\lim\limits_{x\longrightarrow +\infty}f(x)$
            .}
            \qst{1}{\q
              بين أن
              الدالة
            $f$
            متصلة في
            $0$
            .}
            \qst{1}{\sqd
            بين أن
            الدالة
            $f$
            قابلة للاشتقاق في
            $0$
            على اليمين
            ثم أول النتيجة هندسيا
            .
            }
        \qst{1}{\sq
        ادرس قابلية اشتقاق الدالة
        $f$
        في
        $0$
        على اليسار ثم أول النتيجة هندسيا
        .
        }
        \qst{0.5}{\sq
        هل الدالة
        $f$
        قابلة للإشتقاق في
        $0$
        ؟ علل جوابك؟
        .
        }
        \qst{1,25}{\sqd

        بين أن
        :
        $(\forall x\in \mathbb{R}^+): f'(x)=\dfrac{2}{\pi(2+x)\sqrt{1+x}}$.
        }

        \qst{1,25}{\sq

        احسب
        $f'(x)$
        لكل
        $x$
 من
 $\big[\dfrac{-1}{\sqrt{3}};0\big[$.}

 \qst{}{\q
 لتكن

        $g$
        قصور الدالة
        $f$
        على المجال
        $\mathbb{R^+}$.}

        \qst{1}{\sq
     بين أن الدالة
     $g$
تقابل من
        $\mathbb{R^+}$
        نحو مجال
        $J$
        يتم تحديده
        .
        }
        \qst{1}{\sq
        حدد
        $g^{-1}(x)$
        لكل
        $x$
        من
        $J$.}

            \hline
%-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
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    \centering
    \Large
    والله ولي التوفيق
\end{document}




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