Devoir 2 S02 en limites, dérivation et vecteurs l'espace v2
📅 February 08, 2024 | 👁️ Views: 171

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Prof MOSAID & Control 2 -- 1BACSF-1 & 2h \\
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\textbf{\underline{Exercice 1:(7.5pts)}}\\
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3 & 1)- Calculer les limites suivantes: (utiliser les nombres dérivés)\\
& \hspace*{0.5cm} $\displaystyle{\lim_{x \to \pi } \frac{cosx+1}{x-\pi} }$ \hspace*{0.2cm};\hspace*{0.2cm}
$\displaystyle{\lim_{x \to 1} \frac{x^3-\sqrt{x}+2x-2}{x-1} }$ \\
& \\
1.5 & 2)- Calculer le nombre dérivé: $f(x)=\sqrt{x^2+1}$ et $x_0=0$ \\
& \\
3 & 3)- Donner l'équation de la tangente au point $x_0=2$ de $f(x) = \frac{x+1}{x-1}$ \hspace*{0.9cm}\\
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\textbf{\underline{Exercice 2:(8pts)}}\\
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2$\times$4 & Calculer les fonctions dérivées des fonctions:\\
&\\
& \hspace*{0.5cm} $f(x)=-3x^3-7x^2+\sqrt{x}-7$ \hspace*{0.2cm};\hspace*{0.2cm} $f(x) = \frac{2x-3}{x^2+1}$ \hspace*{0.2cm};
\hspace*{0.2cm} $f(x)=\sqrt{x}sin(2x)$ \hspace*{0.2cm};\hspace*{0.2cm} $f(x) = \frac{x^2-3x-1}{x+1}$ \\
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\textbf{\underline{Exercice 3:(4.5pts)}}\\
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& Soit le parallèlogramme $ABCDEFGH$ \\
3 & 1)- Simplifier les sommes :\\
& \\
& \hspace*{0.5cm}$\overrightarrow{HG}+\overrightarrow{CB}$ \hspace*{0.2cm};\hspace*{0.2cm}
$\overrightarrow{HE}+\overrightarrow{HG}+\overrightarrow{FH}$
\hspace*{0.2cm};\hspace*{0.2cm} $\overrightarrow{GH}-\overrightarrow{FG}+\overrightarrow{GC}$\\
&\\
1.5 & 2)- Montrer que les vecteurs $\overrightarrow{BE}$, $\overrightarrow{BC}$ et $\overrightarrow{BH}$ \\
& \hspace*{0.5cm} sont coplanaires. \\
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